(2x+1)^2=4(x+7)

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Solution for (2x+1)^2=4(x+7) equation: 



(2x+1)^2=4(x+7)

We move all terms to the left:

(2x+1)^2-(4(x+7))=0



We calculate terms in parentheses: -(4(x+7)), so:

4(x+7)

We multiply parentheses

4x+28

Back to the equation:

-(4x+28)



We get rid of parentheses

(2x+1)^2-4x-28=0

We add all the numbers together, and all the variables

-4x+(2x+1)^2-28=0

We move all terms containing x to the left, all other terms to the right

-4x+(2x+1)^2=28

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